Total freshman = 58. Number of freshman who prefer cheese toppings= 14. Determined the probability that a freshman prefer cheese toppings. Round to the nearest thousandth

Answer:The probability that a freshman prefer cheese toppings  is   0.241Step-by-step explanation:Probability of any event E =  [tex]\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}[/tex]Here, let E   :  Event of choosing cheese toppingsSo, the number of favorable outcomes = 14Total number of outcomes = 58So, [tex]P(E) =  \frac{\textrm{Number of students who like cheese toppings}}{\textrm{Total number of students}}[/tex]or, P(E) = [tex]\frac{14}{58} = 0.241379[/tex]So,the probability that a freshman prefer cheese toppings  is   0.241379 Rounding of 0.241379  to the nearest thousandth, we getHere , in 0.241379 thousandth digit is 3, and 3 < 5, so the value of P(E) = 0.241